X^2+15x-1800=0

Solution for X^2+15x-1800=0 equation:

X^2+15X-1800=0

a = 1; b = 15; c = -1800;
Δ = b2-4ac
Δ = 152-4·1·(-1800)
Δ = 7425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7425}=\sqrt{225*33}=\sqrt{225}*\sqrt{33}=15\sqrt{33}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15\sqrt{33}}{2*1}=\frac{-15-15\sqrt{33}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15\sqrt{33}}{2*1}=\frac{-15+15\sqrt{33}}{2}
$